4n^2-52n+168=n-7-n+6

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Solution for 4n^2-52n+168=n-7-n+6 equation: 



4n^2-52n+168=n-7-n+6

We move all terms to the left:

4n^2-52n+168-(n-7-n+6)=0

We add all the numbers together, and all the variables

4n^2-52n+168-(-1)=0

We add all the numbers together, and all the variables

4n^2-52n+169=0

a = 4; b = -52; c = +169;
Δ = b2-4ac
Δ = -522-4·4·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{52}{8}=6+1/2$

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